Year 11 in England
10th grade geometry
30 10th grade geometry skills, each with a worked example, free practice that checks every answer, and a printable worksheet. Start with a mixed review, or jump to the skill you need.
Mixed review
Ten questions drawn from every skill below.
Circle theorems
CCSS HSG.C.A.2CCSS HSG.C.A.3England: GCSE Higher Geometry
Example
ABCD is a cyclic quadrilateral. Angle A = 110°. What is angle C?
- Opposite angles in a cyclic quadrilateral add up to 180°.
- 70°
Answer: 70
Vectors
CCSS HSN.VM.A.1CCSS HSN.VM.B.4England: GCSE Higher Geometry
Example
a = (3, −3) and b = (−6, 6). Find 3a + 3b. Type it like (2, −1).
- 3a = (9, −9)
- 3b = (−18, 18)
- (−9, 9)
Answer: (−9, 9)
Pythagoras and trigonometry in 3D
CCSS HSG.SRT.C.8England: GCSE Higher Geometry
Example
A cuboid measures 7 cm × 10 cm × 2 cm. Find the length of its space diagonal, to 1 decimal place.
- 7² + 10² + 2² = 153
- √153 ≈ 12.4 cm
Answer: 12.4
Builds on: Pythagoras' theorem, Trigonometric ratios: SOH CAH TOA
Equation of a circle
CCSS HSG.GPE.A.1England: GCSE Higher Algebra
Example
What is the centre of the circle (x + 6)² + (y − 5)² = 16? Type it like (2, −1).
- (−6, 5)
Answer: (−6, 5)
Give the reason for each step in an angle argument
CCSS HSG.CO.C.9England: GCSE Foundation GeometryEngland: GCSE Higher Geometry
Example
A line crosses two parallel lines. Angle p and an angle of 139° are between the parallel lines, on opposite sides of the crossing line (a Z shape). Which reason should go with the step that finds p?
- Alternate angles are equal
Answer: Alternate angles are equal
Builds on: Angles with parallel lines
Choose the congruence test (SSS, SAS, ASA, AAS, RHS)
CCSS HSG.CO.B.8CCSS HSG.SRT.B.5England: GCSE Foundation GeometryEngland: GCSE Higher Geometry
Example
Triangles ABC and DEF have: ∠A = ∠D, AB = DE, ∠B = ∠E. Which test proves they are congruent?
- ASA
Answer: ASA
Builds on: Congruent triangles
Decide whether two triangles are similar
CCSS HSG.SRT.A.2CCSS HSG.SRT.A.3England: GCSE Higher Geometry
Example
Triangle P has sides 5, 7, 8 cm. Triangle Q has sides 14.5, 17.5, 20 cm. Are they similar?
- 14.5 ÷ 5 = 2.9; 17.5 ÷ 7 = 2.5; 20 ÷ 8 = 2.5
- No
Answer: No
Builds on: Similar shapes
Find missing lengths in similar triangles
CCSS HSG.SRT.B.5England: GCSE Foundation GeometryEngland: GCSE Higher Geometry
Example
Triangles ABC and PQR are similar, with AB matching PQ and BC matching QR. AB = 7 cm, PQ = 28 cm and BC = 10 cm. Find QR.
- k = 28 ÷ 7 = 4
- QR = 10 × 4 = 40 cm
Answer: 40
Builds on: Similar shapes
Use length, area and volume scale factors
CCSS HSG.GMD.A.3CCSS 7.G.A.1England: GCSE Higher Geometry
Example
Two similar shapes have lengths in the ratio 1 : 3. The smaller has area 14 cm². What is the area of the larger?
- 14 × 3² = 14 × 9 = 126 cm²
Answer: 126
Builds on: Find missing lengths in similar triangles
Leads to: Find the volume of a frustum
Solve for x using the angle sum of a triangle
CCSS HSG.CO.C.10CCSS 8.G.A.5England: GCSE Foundation Geometry
Example
The angles of a triangle are (x − 6)°, (3x)° and (x + 11)°. Find x.
- 5x + 5 = 180
- x = 35
Answer: 35
Use the exterior angle of a triangle
CCSS HSG.CO.C.10CCSS 8.G.A.5England: GCSE Foundation Geometry
Example
A triangle has interior angles 26° and 76°. One side is extended at the third vertex. What is the exterior angle there?
- 26° + 76° = 102°
Answer: 102
Builds on: Classify triangles; angles in a triangle
Find angles in isosceles triangles
CCSS HSG.CO.C.10England: GCSE Foundation Geometry
Example
An isosceles triangle has an angle of 64° between its two equal sides. Find one of the other angles.
- (180° − 64°) ÷ 2 = 58°
Answer: 58
Builds on: Classify triangles; angles in a triangle
Find the point that divides a segment in a given ratio
CCSS HSG.GPE.B.6England: GCSE Higher Geometry
Example
P divides AB so that AP : PB = 2 : 1. A is (−5, 1) and P is (1, 7). Find B. Type it like (2, −1).
- one part = (3, 3)
- (4, 10)
Answer: (4, 10)
Builds on: Find a missing endpoint from a midpoint
Find exact distances between points and test for right angles
CCSS HSG.GPE.B.4CCSS HSG.GPE.B.7England: GCSE Higher Geometry
Example
Find the exact distance between (5, 3) and (6, −4). Simplify the surd.
- d = √(1² + 7²) = √50
- = 5√2
Answer: 5√2
Write the equation of a circle from its centre and radius
CCSS HSG.GPE.A.1England: GCSE Higher Algebra
Example
Which is the equation of the circle with centre (−1, −1) and radius 4?
- (x + 1)² + (y + 1)² = 16
Answer: (x + 1)² + (y + 1)² = 16
Builds on: Equation of a circle
Leads to: Find the centre and radius from x² + y² + Dx + Ey + F = 0
Find the centre and radius from x² + y² + Dx + Ey + F = 0
CCSS HSG.GPE.A.1England: A-level Pure Mathematics
Example
Find the centre of the circle x² + y² + 6x − 12y + 36 = 0. Type it like (2, −1).
- (x + 3)² + (y − 6)² = 9
- (−3, 6)
Answer: (−3, 6)
Circle theorems: angle at the centre and angle in a semicircle
CCSS HSG.C.A.2England: GCSE Higher Geometry
Example
O is the centre of a circle. A, B and C are on the circle, with C on the major arc. ∠ACB = 49°. Find ∠AOB.
- ∠AOB = 2 × 49° = 98°
Answer: 98
Builds on: Circle theorems
Circle theorems: cyclic quadrilaterals and angles in the same segment
CCSS HSG.C.A.3England: GCSE Higher Geometry
Example
ABCD is a cyclic quadrilateral. ∠DAB = 128°. Find ∠BCD.
- 180° − 128° = 52°
Answer: 52
Builds on: Circle theorems
Circle theorems: tangents and radii
CCSS HSG.C.A.2CCSS HSG.C.A.4England: GCSE Higher Geometry
Example
PA and PB are tangents from P to a circle with centre O, touching it at A and B. ∠APB = 49°. Find ∠AOB.
- ∠OAP = ∠OBP = 90°
- ∠AOB = 360° − 90° − 90° − 49° = 131°
Answer: 131
Builds on: Circle theorems, Pythagoras' theorem
Circle theorems: the alternate segment theorem
CCSS HSG.C.A.2England: GCSE Higher Geometry
Example
A tangent touches a circle at A. Chord AB makes an angle of 61° with the tangent. C is a point on the circle in the other segment. Find ∠ACB.
- ∠ACB = 61°
Answer: 61
Builds on: Circle theorems: tangents and radii
Name the circle theorem that justifies a step
CCSS HSG.C.A.2CCSS HSG.C.A.3England: GCSE Higher Geometry
Example
O is the centre of the circle. Which theorem justifies this step? ∠OTP = 90°, where PT touches the circle at T
- A tangent is perpendicular to the radius
Answer: A tangent is perpendicular to the radius
Find the angle or radius from an arc length or sector area
CCSS HSG.C.B.5England: GCSE Higher Geometry
Example
A sector of a circle with radius 3 cm has an arc length of 3π cm. Find the angle of the sector in degrees.
- θ/360 = 3π ÷ 6π
- θ = 180°
Answer: 180
Builds on: Arc length and sector area
Find the perimeter of a sector
CCSS HSG.C.B.5England: GCSE Higher Geometry
Example
Find the perimeter of a sector with radius 13 cm and angle 210°. Give your answer to 1 decimal place.
- arc = 210/360 × 2π × 13 ≈ 47.647
- P = 47.647 + 26 ≈ 73.6 cm
Answer: 73.6
Builds on: Arc length and sector area
Find the volume of composite solids
CCSS HSG.GMD.A.3CCSS HSG.MG.A.1England: GCSE Higher Geometry
Example
A rocket model is a cylinder (radius 5 cm, height 9 cm) with a cone (same radius, height 9 cm) on top. Find its volume to 1 decimal place.
- π × 5² × 9 ≈ 706.86
- ⅓ × π × 5² × 9 ≈ 235.62
- ≈ 942.5 cm³
Answer: 942.5
Builds on: Volume of cylinders, cones and spheres
Leads to: Find the volume of a frustum
Find surface areas of cones, spheres and hemispheres
CCSS HSG.GMD.A.3England: GCSE Higher Geometry
Example
Find the surface area of a sphere of radius 12 cm. Give an exact answer in terms of π.
- 4 × π × 12² = 576π cm²
Answer: 576*pi
Find the volume of a frustum
CCSS HSG.GMD.A.3CCSS HSG.MG.A.1England: GCSE Higher Geometry
Example
A cone has base radius 18 cm and height 12 cm. The top is cut off parallel to the base, leaving a small cone of radius 12 cm and height 8 cm removed. Find the volume of the frustum that is left, to 1 decimal place.
- ⅓π(18² × 12 − 12² × 8)
- ≈ 2865.1 cm³
Answer: 2865.1
Write the vector between two points
CCSS HSN.VM.A.2England: GCSE Higher Geometry
Example
P is (5, −2) and the vector PQ is (−1, 5). Find the coordinates of Q. Type them like (2, −1).
- (4, 3)
Answer: (4, 3)
Builds on: Vectors
Use the magnitude of a vector in context
CCSS HSN.VM.A.1CCSS HSN.VM.A.3England: GCSE Higher Geometry
Example
Find the magnitude of (7, 6) to 1 decimal place.
- √(49 + 36) = √85
- ≈ 9.2
Answer: 9.2
Builds on: Vectors
Express vector paths in terms of a and b
CCSS HSN.VM.B.4England: GCSE Higher Geometry
Example
OA = a and OB = b. M is the midpoint of AB. Find OM in terms of a and b.
- OM = OA + ½AB = a + ½(b − a)
- ½a + ½b
Answer: ½a + ½b
Builds on: Vectors
Leads to: Show that vectors are parallel or points are collinear
Show that vectors are parallel or points are collinear
CCSS HSN.VM.B.5England: GCSE Higher Geometry
Example
Is 8a − 4b parallel to −4a + 3b?
- 8 ÷ (−4) = −2; −4 ÷ 3 = −1.333
- No
Answer: No
Builds on: Express vector paths in terms of a and b
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