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Newton's law of gravitation and field strength

12th grade (Year 13 in England) · 16 questions · Common Core: NGSS.HS-PS2-4 · England: A level Physics: Gravitational fields (extension)

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  1. Question 1

    Who first published the law of universal gravitation?

    • A. Albert Einstein
    • B. Johannes Kepler
    • C. Isaac Newton
    • D. Galileo Galilei
  2. Question 2

    Calculate the gravitational field strength at the surface of Earth, in N/kg. Mass = 5.97 × 10²⁴ kg, radius = 6.37 × 10⁶ m, G = 6.67 × 10⁻¹¹ N m²/kg². (g = G M ÷ r²; give 1 decimal place)

    AnswerN/kg

  3. Question 3

    The distance between two masses is multiplied by 2. By what factor does the gravitational force between them change? (F = G m₁ m₂ ÷ r²; give 4 decimal places if needed)

    Answer

  4. Question 4

    Who first published the law of universal gravitation?

    • A. Isaac Newton
    • B. Albert Einstein
    • C. Johannes Kepler
    • D. Galileo Galilei
  5. Question 5

    Calculate the gravitational field strength at the surface of Earth, in N/kg. Mass = 5.97 × 10²⁴ kg, radius = 6.37 × 10⁶ m, G = 6.67 × 10⁻¹¹ N m²/kg². (g = G M ÷ r²; give 1 decimal place)

    AnswerN/kg

  6. Question 6

    The distance between two masses is multiplied by 3. By what factor does the gravitational force between them change? (F = G m₁ m₂ ÷ r²; give 4 decimal places if needed)

    Answer

  7. Question 7

    Why is the value of g slightly smaller at the top of a high mountain?

    • A. It is colder
    • B. You are slightly further from Earth's centre
    • C. There is less air
    • D. Mountains have less mass
  8. Question 8

    Calculate the gravitational field strength at the surface of Jupiter, in N/kg. Mass = 1.9 × 10²⁷ kg, radius = 6.99 × 10⁷ m, G = 6.67 × 10⁻¹¹ N m²/kg². (g = G M ÷ r²; give 1 decimal place)

    AnswerN/kg

  9. Question 9

    One of two masses is multiplied by 0.5 and the distance stays the same. By what factor does the gravitational force change? (F = G m₁ m₂ ÷ r²)

    Answer

  10. Question 10

    Who first published the law of universal gravitation?

    • A. Galileo Galilei
    • B. Albert Einstein
    • C. Isaac Newton
    • D. Johannes Kepler
  11. Question 11

    Calculate the gravitational field strength at the surface of Mars, in N/kg. Mass = 6.42 × 10²³ kg, radius = 3.39 × 10⁶ m, G = 6.67 × 10⁻¹¹ N m²/kg². (g = G M ÷ r²; give 1 decimal place)

    AnswerN/kg

  12. Question 12

    The distance between two masses is multiplied by 0.5. By what factor does the gravitational force between them change? (F = G m₁ m₂ ÷ r²; give 4 decimal places if needed)

    Answer

  13. Question 13

    Why is the value of g slightly smaller at the top of a high mountain?

    • A. It is colder
    • B. Mountains have less mass
    • C. There is less air
    • D. You are slightly further from Earth's centre
  14. Question 14

    Calculate the gravitational field strength at the surface of Earth, in N/kg. Mass = 5.97 × 10²⁴ kg, radius = 6.37 × 10⁶ m, G = 6.67 × 10⁻¹¹ N m²/kg². (g = G M ÷ r²; give 1 decimal place)

    AnswerN/kg

  15. Question 15

    One of two masses is multiplied by 2 and the distance stays the same. By what factor does the gravitational force change? (F = G m₁ m₂ ÷ r²)

    Answer

  16. Question 16

    Why do all objects near Earth's surface fall with the same acceleration (ignoring air)?

    • A. Light objects are pulled harder
    • B. Heavier objects feel no extra force
    • C. A larger mass feels a larger force, but also needs more force to accelerate, so a = g for all
    • D. Gravity does not depend on mass

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Answer key: Newton's law of gravitation and field strength

  1. 1. C. Isaac Newton

  2. 2. 9.8 N/kg

  3. 3. 0.25

  4. 4. A. Isaac Newton

  5. 5. 9.8 N/kg

  6. 6. 0.1111

  7. 7. B. You are slightly further from Earth's centre

  8. 8. 25.9 N/kg

  9. 9. 0.5

  10. 10. C. Isaac Newton

  11. 11. 3.7 N/kg

  12. 12. 4

  13. 13. D. You are slightly further from Earth's centre

  14. 14. 9.8 N/kg

  15. 15. 2

  16. 16. C. A larger mass feels a larger force, but also needs more force to accelerate, so a = g for all