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Distance from the area under a velocity–time graph

10th grade (Year 11 in England) · 16 questions · Common Core: NGSS.HS-PS2-1, NGSS.SEP 5 · England: GCSE Combined Science: Forces (Higher: area under velocity–time graph)

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  1. Question 1

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (4 s, 4 m/s). How far does the object travel in this time, in m?

    Answerm

  2. Question 2

    Velocity–time graph: (0 s, 0 m/s) → (5 s, 10 m/s) → (10 s, 10 m/s) → (15 s, 0 m/s). What is the total distance travelled, in m?

    xy24681012141624681012140(0, 0)ABC

    Answerm

  3. Question 3

    A train travels at a constant 15 m/s for 20 s. On a velocity–time graph, what is the area under the line, and so the distance travelled, in m?

    Answerm

  4. Question 4

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (10 s, 20 m/s). How far does the object travel in this time, in m?

    Answerm

  5. Question 5

    Velocity–time graph: (0 s, 0 m/s) → (4 s, 12 m/s) → (14 s, 12 m/s) → (24 s, 0 m/s). What is the total distance travelled, in m?

    xy61218246120(0, 0)ABC

    Answerm

  6. Question 6

    A train travels at a constant 10 m/s for 40 s. On a velocity–time graph, what is the area under the line, and so the distance travelled, in m?

    Answerm

  7. Question 7

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (10 s, 20 m/s). How far does the object travel in this time, in m?

    Answerm

  8. Question 8

    Velocity–time graph: (0 s, 0 m/s) → (4 s, 8 m/s) → (14 s, 8 m/s) → (24 s, 0 m/s). What is the total distance travelled, in m?

    xy61218246120(0, 0)ABC

    Answerm

  9. Question 9

    A train travels at a constant 25 m/s for 40 s. On a velocity–time graph, what is the area under the line, and so the distance travelled, in m?

    Answerm

  10. Question 10

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (10 s, 10 m/s). How far does the object travel in this time, in m?

    Answerm

  11. Question 11

    Velocity–time graph: (0 s, 0 m/s) → (5 s, 5 m/s) → (10 s, 5 m/s) → (14 s, 0 m/s). What is the total distance travelled, in m?

    xy2468101214162468100(0, 0)ABC

    Answerm

  12. Question 12

    A train travels at a constant 12 m/s for 40 s. On a velocity–time graph, what is the area under the line, and so the distance travelled, in m?

    Answerm

  13. Question 13

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (4 s, 12 m/s). How far does the object travel in this time, in m?

    Answerm

  14. Question 14

    Velocity–time graph: (0 s, 0 m/s) → (4 s, 12 m/s) → (9 s, 12 m/s) → (19 s, 0 m/s). What is the total distance travelled, in m?

    xy612186120(0, 0)ABC

    Answerm

  15. Question 15

    A train travels at a constant 10 m/s for 20 s. On a velocity–time graph, what is the area under the line, and so the distance travelled, in m?

    Answerm

  16. Question 16

    A velocity–time graph rises in a straight line from (0 s, 0 m/s) to (4 s, 8 m/s). How far does the object travel in this time, in m?

    Answerm

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Answer key: Distance from the area under a velocity–time graph

  1. 1. 8 m

  2. 2. 100 m

  3. 3. 300 m

  4. 4. 100 m

  5. 5. 204 m

  6. 6. 400 m

  7. 7. 100 m

  8. 8. 136 m

  9. 9. 1000 m

  10. 10. 50 m

  11. 11. 47.5 m

  12. 12. 480 m

  13. 13. 24 m

  14. 14. 144 m

  15. 15. 200 m

  16. 16. 16 m