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Solve a linear system by substitution

9th grade (Year 10 in England) Β· 16 questions Β· Common Core: HSA.REI.C.6 Β· England: GCSE Foundation Algebra, GCSE Higher Algebra

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  1. Question 1

    Solve the system: y = βˆ’2x + 5 3x βˆ’ 4y = 24 Type the solution like (2, βˆ’1).

    Answer

  2. Question 2

    Solve the system: x = βˆ’y βˆ’ 1 βˆ’x + 3y = βˆ’23 Type the solution like (2, βˆ’1).

    Answer

  3. Question 3

    To solve y = βˆ’4x βˆ’ 2 and βˆ’4x βˆ’ 5y = 7 by substitution, which is the correct next line?

    • A. βˆ’4x + 5(βˆ’4x βˆ’ 2) = 7
    • B. βˆ’4x βˆ’ 2 βˆ’ 5y = 7
    • C. βˆ’4x βˆ’ 5Β·βˆ’4x βˆ’ 2 = 7
    • D. βˆ’4x βˆ’ 5(βˆ’4x βˆ’ 2) = 7
  4. Question 4

    Solve the system: y = βˆ’3x + 7 2x βˆ’ y = 3 Type the solution like (2, βˆ’1).

    Answer

  5. Question 5

    Solve the system: x = 3y + 3 βˆ’4x βˆ’ 5y = βˆ’29 Type the solution like (2, βˆ’1).

    Answer

  6. Question 6

    To solve y = 4x βˆ’ 6 and βˆ’x βˆ’ 4y = βˆ’13 by substitution, which is the correct next line?

    • A. 4x βˆ’ 6 βˆ’ 4y = βˆ’13
    • B. βˆ’x βˆ’ 4(4x βˆ’ 6) = βˆ’13
    • C. βˆ’x + 4(4x βˆ’ 6) = βˆ’13
    • D. βˆ’x βˆ’ 4Β·4x βˆ’ 6 = βˆ’13
  7. Question 7

    Solve the system: y = 2x + 2 βˆ’5x βˆ’ y = 5 Type the solution like (2, βˆ’1).

    Answer

  8. Question 8

    Solve the system: x = βˆ’2y + 17 3x βˆ’ y = 9 Type the solution like (2, βˆ’1).

    Answer

  9. Question 9

    To solve y = x + 2 and 4x βˆ’ 4y = 4 by substitution, which is the correct next line?

    • A. 4x βˆ’ 4Β·x + 2 = 4
    • B. x + 2 βˆ’ 4y = 4
    • C. 4x βˆ’ 4(x + 2) = 4
    • D. 4x + 4(x + 2) = 4
  10. Question 10

    Solve the system: y = 3x + 7 βˆ’5x + y = 9 Type the solution like (2, βˆ’1).

    Answer

  11. Question 11

    Solve the system: x = 3y βˆ’ 8 βˆ’2x βˆ’ y = βˆ’5 Type the solution like (2, βˆ’1).

    Answer

  12. Question 12

    To solve y = 3x βˆ’ 3 and βˆ’x βˆ’ 3y = βˆ’11 by substitution, which is the correct next line?

    • A. βˆ’x βˆ’ 3(3x βˆ’ 3) = βˆ’11
    • B. βˆ’x βˆ’ 3Β·3x βˆ’ 3 = βˆ’11
    • C. βˆ’x + 3(3x βˆ’ 3) = βˆ’11
    • D. 3x βˆ’ 3 βˆ’ 3y = βˆ’11
  13. Question 13

    Solve the system: y = βˆ’4x + 23 2x + 3y = 19 Type the solution like (2, βˆ’1).

    Answer

  14. Question 14

    Solve the system: x = βˆ’y βˆ’ 5 βˆ’x βˆ’ 2y = 6 Type the solution like (2, βˆ’1).

    Answer

  15. Question 15

    To solve y = βˆ’2x + 1 and βˆ’5x βˆ’ 4y = 1 by substitution, which is the correct next line?

    • A. βˆ’5x + 4(βˆ’2x + 1) = 1
    • B. βˆ’5x βˆ’ 4Β·βˆ’2x + 1 = 1
    • C. βˆ’5x βˆ’ 4(βˆ’2x + 1) = 1
    • D. βˆ’2x + 1 βˆ’ 4y = 1
  16. Question 16

    Solve the system: y = 4x + 12 βˆ’5x + 4y = 15 Type the solution like (2, βˆ’1).

    Answer

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  1. (4, βˆ’3)
  2. (5, βˆ’6)
  3. βˆ’4x βˆ’ 5(βˆ’4x βˆ’ 2) = 7
  4. (2, 1)
  5. (6, 1)
  6. βˆ’x βˆ’ 4(4x βˆ’ 6) = βˆ’13
  7. (βˆ’1, 0)
  8. (5, 6)
  9. 4x βˆ’ 4(x + 2) = 4
  10. (βˆ’1, 4)
  11. (1, 3)
  12. βˆ’x βˆ’ 3(3x βˆ’ 3) = βˆ’11
  13. (5, 3)
  14. (βˆ’4, βˆ’1)
  15. βˆ’5x βˆ’ 4(βˆ’2x + 1) = 1
  16. (βˆ’3, 0)