Find a curve from its gradient and a point
12th grade (Year 13 in England) · 16 questions · Common Core: HSF.BF.B.4 · England: A-level Pure Mathematics
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Question 1
dy/dx = 4x − 3 and the curve passes through (3, 7). Find y in terms of x.
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Question 2
A cyclist's velocity is v = 1 + 2t m/s. Starting from s = 0, how far has she travelled after 6 seconds?
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Question 3
dy/dx = −8x + 4 and the curve passes through (−2, 9). Find y in terms of x.
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Question 4
A cyclist's velocity is v = 5 + 6t m/s. Starting from s = 0, how far has she travelled after 3 seconds?
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Question 5
dy/dx = −6x − 5 and the curve passes through (0, 2). Find y in terms of x.
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Question 6
A cyclist's velocity is v = 1 + 2t m/s. Starting from s = 0, how far has she travelled after 6 seconds?
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Question 7
dy/dx = −4x + 5 and the curve passes through (1, 7). Find y in terms of x.
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Question 8
A cyclist's velocity is v = 1 + 6t m/s. Starting from s = 0, how far has she travelled after 1 seconds?
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Question 9
dy/dx = −8x + 2 and the curve passes through (2, 4). Find y in terms of x.
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Question 10
A cyclist's velocity is v = 1 + 6t m/s. Starting from s = 0, how far has she travelled after 4 seconds?
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Question 11
dy/dx = 6x + 6 and the curve passes through (1, 3). Find y in terms of x.
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Question 12
A cyclist's velocity is v = 2 + 2t m/s. Starting from s = 0, how far has she travelled after 5 seconds?
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Question 13
dy/dx = −2x + 5 and the curve passes through (2, 9). Find y in terms of x.
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Question 14
A cyclist's velocity is v = 3 + 6t m/s. Starting from s = 0, how far has she travelled after 6 seconds?
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Question 15
dy/dx = 2x + 2 and the curve passes through (1, 1). Find y in terms of x.
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Question 16
A cyclist's velocity is v = 3 + 6t m/s. Starting from s = 0, how far has she travelled after 2 seconds?
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