Estimate a limit from a table of values
12th grade (Year 13 in England) Β· 16 questions Β· Common Core: HSF.IF.A.2 Β· England: A-level Pure Mathematics
Name
Date
Score/ 16
Question 1
f(x) = (xΒ² β 36)/(x β 6). It has no value at x = 6 itself. x: 5.9 | 5.99 | 5.999 | 6.001 | 6.01 | 6.1 f(x): 11.9 | 11.99 | 11.999 | 12.001 | 12.01 | 12.1 Estimate lim(xβ6) f(x).
Answer
Question 2
g(x) = (xΒ³ + 27)/(x + 3). x: β3.1 | β3.01 | β3.001 | β2.999 | β2.99 | β2.9 g(x): 27.91 | 27.0901 | 27.009 | 26.991 | 26.9101 | 26.11 Estimate lim(xββ3) g(x).
Answer
Question 3
x: β0.1 | β0.01 | β0.001 | 0.001 | 0.01 | 0.1 f(x): β1 | β1 | β1 | 1 | 1 | 1 Does lim(xβ0) f(x) exist?
- A. Yes
- B. No: the two sides approach different values
Question 4
f(x) = (xΒ² β 36)/(x β 6). It has no value at x = 6 itself. x: 5.9 | 5.99 | 5.999 | 6.001 | 6.01 | 6.1 f(x): 11.9 | 11.99 | 11.999 | 12.001 | 12.01 | 12.1 Estimate lim(xβ6) f(x).
Answer
Question 5
g(x) = (xΒ³ β 27)/(x β 3). x: 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 g(x): 26.11 | 26.9101 | 26.991 | 27.009 | 27.0901 | 27.91 Estimate lim(xβ3) g(x).
Answer
Question 6
x: β1.1 | β1.01 | β1.001 | β0.999 | β0.99 | β0.9 f(x): β2.1 | β2.01 | β2.001 | β1.999 | β1.99 | β1.9 Does lim(xββ1) f(x) exist?
- A. Yes
- B. No: the two sides approach different values
Question 7
f(x) = (xΒ² β 16)/(x β 4). It has no value at x = 4 itself. x: 3.9 | 3.99 | 3.999 | 4.001 | 4.01 | 4.1 f(x): 7.9 | 7.99 | 7.999 | 8.001 | 8.01 | 8.1 Estimate lim(xβ4) f(x).
Answer
Question 8
g(x) = (xΒ³ β 8)/(x β 2). x: 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 g(x): 11.41 | 11.9401 | 11.994 | 12.006 | 12.0601 | 12.61 Estimate lim(xβ2) g(x).
Answer
Question 9
x: 1.9 | 1.99 | 1.999 | 2.001 | 2.01 | 2.1 f(x): 3.9 | 3.99 | 3.999 | 4.001 | 4.01 | 4.1 Does lim(xβ2) f(x) exist?
- A. Yes
- B. No: the two sides approach different values
Question 10
f(x) = (xΒ² β 25)/(x β 5). It has no value at x = 5 itself. x: 4.9 | 4.99 | 4.999 | 5.001 | 5.01 | 5.1 f(x): 9.9 | 9.99 | 9.999 | 10.001 | 10.01 | 10.1 Estimate lim(xβ5) f(x).
Answer
Question 11
g(x) = (xΒ³ + 1)/(x + 1). x: β1.1 | β1.01 | β1.001 | β0.999 | β0.99 | β0.9 g(x): 3.31 | 3.0301 | 3.003 | 2.997 | 2.9701 | 2.71 Estimate lim(xββ1) g(x).
Answer
Question 12
x: 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 f(x): 5.9 | 5.99 | 5.999 | 6.001 | 6.01 | 6.1 Does lim(xβ3) f(x) exist?
- A. Yes
- B. No: the two sides approach different values
Question 13
f(x) = (xΒ² β 4)/(x + 2). It has no value at x = β2 itself. x: β2.1 | β2.01 | β2.001 | β1.999 | β1.99 | β1.9 f(x): β4.1 | β4.01 | β4.001 | β3.999 | β3.99 | β3.9 Estimate lim(xββ2) f(x).
Answer
Question 14
g(x) = (xΒ³ β 1)/(x β 1). x: 0.9 | 0.99 | 0.999 | 1.001 | 1.01 | 1.1 g(x): 2.71 | 2.9701 | 2.997 | 3.003 | 3.0301 | 3.31 Estimate lim(xβ1) g(x).
Answer
Question 15
x: 0.9 | 0.99 | 0.999 | 1.001 | 1.01 | 1.1 f(x): β1 | β1 | β1 | 1 | 1 | 1 Does lim(xβ1) f(x) exist?
- A. Yes
- B. No: the two sides approach different values
Question 16
f(x) = (xΒ² β 9)/(x + 3). It has no value at x = β3 itself. x: β3.1 | β3.01 | β3.001 | β2.999 | β2.99 | β2.9 f(x): β6.1 | β6.01 | β6.001 | β5.999 | β5.99 | β5.9 Estimate lim(xββ3) f(x).
Answer
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