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Math lesson plan · 12th grade (Year 13 in England) · 60 minutes

Solve optimisation problems with calculus

Calculus

CCSS HSA.CED.A.2England: A-level Pure Mathematics

Objective and success criteria

Students will: Solve optimisation problems with calculus.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Find stationary points and decide their nature

Leads to: the next skill in this area.

Materials: Graphing tool or graph paper, Scientific calculators, Mini whiteboards and pens, Printed student sheet (below).

Warm-up · 6 min

  • Quick retrieval from earlier learning (Find stationary points and decide their nature). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. Use calculus to find the stationary point of y = 3x² + 18x + 29. Type it like (2, −1). → (−3, 2)Prompt: At a stationary point, dy/dx = 0.
  2. Find the x-coordinates of the stationary points of y = x³ − 12x² + 36x + 1. Separate them with a comma. → x = 2 or x = 6Prompt: Differentiate and set dy/dx = 0.
  3. y = x³ − 3x² − 24x has a stationary point at x = −2. Is it a maximum or a minimum? (Maximum / Minimum) → MaximumPrompt: Find the second derivative d²y/dx².

Hook · 6 min

  • Show a distance-time graph of a journey and ask how fast it was going at one exact moment.
  • Share the objective: Solve optimisation problems with calculus. Read the success criteria together.

I do: model it · 12 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: A farmer has 80 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(80 − 2x). Find the maximum area in m².
  • Step 1: A = 80x − 2x²
  • Step 2: dA/dx = 80 − 4x = 0 → x = 20
  • Step 3: A = 20 × 40 = 800 m²
  • Answer: 800
  • Pause after each step and ask a student to say what comes next.

We do: guided practice · 12 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. A farmer has 92 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(92 − 2x). Find the maximum area in m². → 1058Prompt: Expand, differentiate and set dA/dx = 0.
  2. An open box is made from a 42 cm square of card by cutting a square of side x cm from each corner and folding up. V = x(42 − 2x)². Find the maximum volume in cm³. → 5488Prompt: Expand V, differentiate and solve dV/dx = 0.

You do: independent practice · 17 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 8 questions are on the student sheet below, with answers in the key.

Exit ticket · 7 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. An open box is made from a 30 cm square of card by cutting a square of side x cm from each corner and folding up. V = x(30 − 2x)². Find the maximum volume in cm³. → 2000Prompt: Expand V, differentiate and solve dV/dx = 0.
  2. A farmer has 28 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(28 − 2x). Find the maximum area in m². → 98Prompt: Expand, differentiate and set dA/dx = 0.

Watch out for

  • Forgetting the constant of integration.
  • Differentiating a product by multiplying the derivatives.

Support and stretch

Support

  • Review first: Find stationary points and decide their nature.
  • Use concrete materials: graphing tool or graph paper.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/math/grade-12.

Free lesson plan from eurekami.com/lesson-plan-builder

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Solve optimisation problems with calculus

Name

Date

Score/ 8

  1. Question 1

    An open box is made from a 48 cm square of card by cutting a square of side x cm from each corner and folding up. V = x(48 − 2x)². Find the maximum volume in cm³.

    Answer

  2. Question 2

    An app sells subscriptions. At price p, it sells 72 − 3p per day, so revenue R = p(72 − 3p). What price maximises revenue?

    Answer

  3. Question 3

    A farmer has 104 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(104 − 2x). Find the maximum area in m².

    Answer

  4. Question 4

    An open box is made from a 12 cm square of card by cutting a square of side x cm from each corner and folding up. V = x(12 − 2x)². Find the maximum volume in cm³.

    Answer

  5. Question 5

    An app sells subscriptions. At price p, it sells 76 − 2p per day, so revenue R = p(76 − 2p). What price maximises revenue?

    Answer

  6. Question 6

    A farmer has 40 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(40 − 2x). Find the maximum area in m².

    Answer

  7. Question 7

    An app sells subscriptions. At price p, it sells 190 − 5p per day, so revenue R = p(190 − 5p). What price maximises revenue?

    Answer

  8. Question 8

    A farmer has 96 m of fencing to make a rectangular pen against a straight wall (the wall is one side). If the two sides at right angles to the wall are x m, the area is A = x(96 − 2x). Find the maximum area in m².

    Answer

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Answer key: Solve optimisation problems with calculus

  1. 1. 8192

  2. 2. 12

  3. 3. 1352

  4. 4. 128

  5. 5. 19

  6. 6. 200

  7. 7. 19

  8. 8. 1152

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