Solve equations with brackets and x on both sides
8th grade (Year 9 in England) · 16 questions · Common Core: 8.EE.C.7.B · England: KS3 Algebra, GCSE Foundation Algebra
Name
Date
Score/ 16
Question 1
Solve: 6(x − 3) = 7x − 19
x =
Question 2
A rectangle is (x + 3) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 3 + 3) = 4(x − 1). Find x.
x =
Question 3
Solve: 5(x − 5) = 2(x + 2) − 41
x =
Question 4
Solve: 2(x + 2) = 3x + 11
x =
Question 5
A rectangle is (x + 6) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 6 + 3) = 4(x − 1). Find x.
x =
Question 6
Solve: 3(x + 5) = 2(x − 4) + 19
x =
Question 7
Solve: 3(x + 4) = x + 14
x =
Question 8
A rectangle is (x + 6) cm long and 3 cm wide. A square has sides of (x − 4) cm. Their perimeters are equal, so 2(x + 6 + 3) = 4(x − 4). Find x.
x =
Question 9
Solve: 3(x + 5) = 5(x − 2) + 29
x =
Question 10
Solve: 5(x + 6) = 6x + 29
x =
Question 11
A rectangle is (x + 3) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 3 + 3) = 4(x − 1). Find x.
x =
Question 12
Solve: 5(x − 5) = 3(x − 4) − 17
x =
Question 13
Solve: 6(x + 4) = 4x + 34
x =
Question 14
A rectangle is (x + 4) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 4 + 3) = 4(x − 1). Find x.
x =
Question 15
Solve: 3(x + 1) = 4(x − 2) + 13
x =
Question 16
Solve: 6(x − 4) = 5x − 19
x =
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