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Solve equations with brackets and x on both sides

8th grade (Year 9 in England) · 16 questions · Common Core: 8.EE.C.7.B · England: KS3 Algebra, GCSE Foundation Algebra

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Date

Score/ 16

  1. Question 1

    Solve: 3(x + 5) = 5(x − 5) + 28

    x =

  2. Question 2

    A rectangle is (x + 1) cm long and 3 cm wide. A square has sides of (x − 2) cm. Their perimeters are equal, so 2(x + 1 + 3) = 4(x − 2). Find x.

    x =

  3. Question 3

    Solve: 2(x − 3) = 3x − 10

    x =

  4. Question 4

    Solve: 4(x + 2) = 2(x − 4) + 6

    x =

  5. Question 5

    A rectangle is (x + 3) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 3 + 3) = 4(x − 1). Find x.

    x =

  6. Question 6

    Solve: 2(x − 6) = x − 4

    x =

  7. Question 7

    Solve: 5(x − 3) = 3(x + 4) − 31

    x =

  8. Question 8

    A rectangle is (x + 3) cm long and 3 cm wide. A square has sides of (x − 1) cm. Their perimeters are equal, so 2(x + 3 + 3) = 4(x − 1). Find x.

    x =

  9. Question 9

    Solve: 2(x + 3) = 5x − 6

    x =

  10. Question 10

    Solve: 5(x + 2) = 6(x − 5) + 43

    x =

  11. Question 11

    A rectangle is (x + 5) cm long and 3 cm wide. A square has sides of (x − 2) cm. Their perimeters are equal, so 2(x + 5 + 3) = 4(x − 2). Find x.

    x =

  12. Question 12

    Solve: 2(x + 5) = 3x + 15

    x =

  13. Question 13

    Solve: 4(x + 3) = 3(x − 1) + 23

    x =

  14. Question 14

    A rectangle is (x + 2) cm long and 3 cm wide. A square has sides of (x − 2) cm. Their perimeters are equal, so 2(x + 2 + 3) = 4(x − 2). Find x.

    x =

  15. Question 15

    Solve: 6(x + 2) = 3x + 24

    x =

  16. Question 16

    Solve: 2(x + 3) = 3(x − 5) + 26

    x =

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  1. x = 6
  2. x = 8
  3. x = 4
  4. x = -5
  5. x = 8
  6. x = 8
  7. x = -2
  8. x = 8
  9. x = 4
  10. x = -3
  11. x = 12
  12. x = -5
  13. x = 8
  14. x = 9
  15. x = 4
  16. x = -5