Solve trigonometric equations between 0° and 360°
12th grade (Year 13 in England) · 16 questions · Common Core: HSF.TF.B.7 · England: A-level Pure Mathematics
Name
Date
Score/ 16
Question 1
Solve cos x = 1/2 for 0° ≤ x < 360°.
- A. 120°, 240°
- B. 60°, 300°
- C. 60°, 120°
- D. 240°, 300°
Question 2
Solve sin x = 0.7, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 3
Solve tan x = −1 for 0° ≤ x < 360°.
- A. 135°, 225°
- B. 45°, 135°
- C. 45°, 315°
- D. 135°, 315°
Question 4
Solve sin x = 0.9, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 5
Solve sin x = −1/2 for 0° ≤ x < 360°.
- A. 150°, 330°
- B. 210°, 330°
- C. 30°, 330°
- D. 150°, 210°
Question 6
Solve sin x = 0.3, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 7
Solve sin x = −√2/2 for 0° ≤ x < 360°.
- A. 135°, 225°
- B. 45°, 225°
- C. 135°, 315°
- D. 225°, 315°
Question 8
Solve sin x = 0.8, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 9
Solve sin x = −1/2 for 0° ≤ x < 360°.
- A. 30°, 210°
- B. 30°, 330°
- C. 210°, 330°
- D. 30°, 150°
Question 10
Solve sin x = 0.7, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 11
Solve cos x = 1/2 for 0° ≤ x < 360°.
- A. 120°, 300°
- B. 60°, 240°
- C. 60°, 300°
- D. 120°, 240°
Question 12
Solve sin x = 0.3, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 13
Solve cos x = −√3/2 for 0° ≤ x < 360°.
- A. 150°, 210°
- B. 30°, 330°
- C. 30°, 210°
- D. 30°, 150°
Question 14
Solve sin x = 0.7, giving the solution between 90° and 180° to 1 decimal place.
Answer
Question 15
Solve sin x = −1/2 for 0° ≤ x < 360°.
- A. 150°, 210°
- B. 210°, 330°
- C. 150°, 330°
- D. 30°, 330°
Question 16
Solve sin x = 0.2, giving the solution between 90° and 180° to 1 decimal place.
Answer
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