Use sin²θ + cos²θ = 1 to find exact values
12th grade (Year 13 in England) · 16 questions · Common Core: HSF.TF.C.8 · England: A-level Pure Mathematics
Name
Date
Score/ 16
Question 1
θ is acute and cos θ = 40/41. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
Question 2
90° < θ < 180° and sin θ = 9/41. Find cos θ as a fraction.
Answer(as a fraction)
Question 3
θ is acute and sin θ = 5/13. Find cos θ as a fraction.
Answer(as a fraction)
Question 4
θ is acute and cos θ = 24/25. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
Question 5
90° < θ < 180° and sin θ = 9/41. Find cos θ as a fraction.
Answer(as a fraction)
Question 6
θ is acute and cos θ = 24/25. Find sin θ as a fraction.
Answer(as a fraction)
Question 7
θ is acute and cos θ = 4/5. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
Question 8
90° < θ < 180° and sin θ = 20/29. Find cos θ as a fraction.
Answer(as a fraction)
Question 9
θ is acute and sin θ = 7/25. Find cos θ as a fraction.
Answer(as a fraction)
Question 10
θ is acute and cos θ = 15/17. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
Question 11
90° < θ < 180° and sin θ = 8/17. Find cos θ as a fraction.
Answer(as a fraction)
Question 12
θ is acute and sin θ = 5/13. Find cos θ as a fraction.
Answer(as a fraction)
Question 13
θ is acute and cos θ = 4/5. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
Question 14
90° < θ < 180° and sin θ = 7/25. Find cos θ as a fraction.
Answer(as a fraction)
Question 15
θ is acute and sin θ = 20/29. Find cos θ as a fraction.
Answer(as a fraction)
Question 16
θ is acute and cos θ = 4/5. Find tan θ as a fraction in simplest form.
Answer(as a fraction)
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