Common Core HSF.IF.A.2 worksheet

Question 1

x: −3.1 | −3.01 | −3.001 | −2.999 | −2.99 | −2.9 f(x): −6.1 | −6.01 | −6.001 | −5.999 | −5.99 | −5.9 Does lim(x→−3) f(x) exist?

• A. Yes
• B. No: the two sides approach different values

Question 2

f(x) = (x² − 4)/(x + 2). It has no value at x = −2 itself. x: −2.1 | −2.01 | −2.001 | −1.999 | −1.99 | −1.9 f(x): −4.1 | −4.01 | −4.001 | −3.999 | −3.99 | −3.9 Estimate lim(x→−2) f(x).

Answer 

Question 3

f(x) = 3x + 9. For what value of x is f(x) = 12?

x = 

Question 4

f(x) = x². Find f(−2 + 1) − f(−2).

Answer 

Question 5

f(x) = 3x − 8 and g(x) = x² − 2. Find f(5) − g(−1).

Answer 

Question 6

f(x) = 2x² − 4x + 2. Find f(−1).

Answer 

Question 7

f(x) = −3x and g(x) = −2x − 6. For which x is f(x) = g(x)?

x = 

Question 8

g(x) = (x³ + 8)/(x + 2). x: −2.1 | −2.01 | −2.001 | −1.999 | −1.99 | −1.9 g(x): 12.61 | 12.0601 | 12.006 | 11.994 | 11.9401 | 11.41 Estimate lim(x→−2) g(x).

Answer 

Question 9

x: 2.9 | 2.99 | 2.999 | 3.001 | 3.01 | 3.1 f(x): 5.9 | 5.99 | 5.999 | 6.001 | 6.01 | 6.1 Does lim(x→3) f(x) exist?

• A. Yes
• B. No: the two sides approach different values

Question 10

f(x) = (x² − 4)/(x + 2). It has no value at x = −2 itself. x: −2.1 | −2.01 | −2.001 | −1.999 | −1.99 | −1.9 f(x): −4.1 | −4.01 | −4.001 | −3.999 | −3.99 | −3.9 Estimate lim(x→−2) f(x).

Answer 

Question 11

f(x) = −3x − 6. For what value of x is f(x) = 12?

x = 

Question 12

f(x) = x² + x. Find f(−2 + 1) − f(−2).

Answer 

Question 13

f(x) = x + 6 and g(x) = x² − 3. Find f(−2) + g(−1).

Answer 

Question 14

f(x) = x² + 5x − 4. Find f(−4).

Answer 

Question 15

f(x) = −2x + 4 and g(x) = −5x + 4. For which x is f(x) = g(x)?

x = 

Question 16

g(x) = (x³ + 27)/(x + 3). x: −3.1 | −3.01 | −3.001 | −2.999 | −2.99 | −2.9 g(x): 27.91 | 27.0901 | 27.009 | 26.991 | 26.9101 | 26.11 Estimate lim(x→−3) g(x).

Answer