Common Core HSA.REI.B.3 worksheet
High school Β· 16 questions Β· Common Core: HSA.REI.B.3, HSA.CED.A.1, HSA.CED.A.4, 8.EE.C.7.A Β· England: GCSE Foundation Algebra, GCSE Higher Algebra
Name
Date
Score/ 16
Question 1
Solve: |x β 3| = 4. Give both solutions, separated by a comma.
x =
Question 2
Solve: x + 7 < 2 or 3x β 2 > β11
- A. x < 2 or x > β9
- B. x < β5 or x > β3
- C. x > β5 or x < β3
- D. β5 < x < β3
Question 3
Solve: |x + 2| = 1. Give both solutions, separated by a comma.
x =
Question 4
Solve: 2(x + 4) > 4x + 2
- A. x < β3
- B. x < 5
- C. x > 3
- D. x < 3
Question 5
Solve: 5|x β 1| + 6 = 26. Give both solutions, separated by a comma.
x =
Question 6
Rearrange 3x + 3y = β18 to make y the subject. Type the expression for y.
Answer
Question 7
For what value of k does 3x β 1 = kx + 3 have no solution?
Answer
Question 8
Solve: |x β 1| < 2
- A. x < β1 or x > 3
- B. β3 < x < 1
- C. β1 < x < 3
- D. x < 3
Question 9
How many solutions does 2|x β 3| β 1 = 5 have?
Answer
Question 10
How many solutions does 4(x β 3) + 8 = 4x β 4 have?
- A. Exactly one solution
- B. No solution
- C. Infinitely many solutions
Question 11
How many integers x satisfy 8 < 5x β 2 < 23?
Answer
Question 12
How many solutions does |x + 4| = β5 have?
Answer
Question 13
Solve: 6x + 10 β€ 52
- A. x β€ 6
- B. x β₯ 7
- C. x β€ 7
- D. x β€ β7
Question 14
Solve aΒ·x β b = cΒ·x for x.
Answer
Question 15
Solve: β1 < βx + 4 < 2
- A. β5 < x < β2
- B. 5 < x < 2
- C. 2 < x < 5
Question 16
Solve: (x + 9)/4 = β2
x =
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