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Math lesson plan Β· 7th grade (Year 8 in England) Β· 60 minutes

Solve two-step equations with negative numbers

Algebra

CCSS 7.EE.B.4.AEngland: KS3 AlgebraEngland: GCSE Foundation Algebra

Objective and success criteria

Students will: Solve two-step equations with negative numbers.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Two-step equations; Divide integers and find missing factors

Leads to: Solve equations of the form p(x + q) = r; Solve two-step equations with a division; Write and solve two-step equations from real situations

Materials: Balance scales or a balance drawing, Algebra tiles, Function machine cards, Mini whiteboards and pens, Printed student sheet (below).

Warm-up Β· 6 min

  • Quick retrieval from earlier learning (Two-step equations; Divide integers and find missing factors). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. βˆ’24 Γ· (βˆ’3) = ? β†’ 8Prompt: Divide the sizes.
  2. Solve: 2x + 10 = 14 β†’ x = 2Prompt: Subtract 10 from both sides.
  3. 54 Γ· (βˆ’9) = ? β†’ -6Prompt: Divide the sizes.

Hook Β· 6 min

  • Show a "think of a number" puzzle and ask the class to work out the starting number.
  • Share the objective: Solve two-step equations with negative numbers. Read the success criteria together.

I do: model it Β· 12 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: Solve: x βˆ’ 11 = βˆ’17
  • Step 1: x = βˆ’17 + 11 = βˆ’6
  • Step 2: x = βˆ’6 Γ· 1 = βˆ’6
  • Answer: x = -6
  • Pause after each step and ask a student to say what comes next.

We do: guided practice Β· 12 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. Solve: 3x βˆ’ 3 = 0 β†’ x = 1Prompt: First undo the subtraction: add 3 on both sides.
  2. Solve: 23 βˆ’ 4x = 19 β†’ x = 1Prompt: Subtract 23 from both sides.

You do: independent practice Β· 17 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 8 questions are on the student sheet below, with answers in the key.

Exit ticket Β· 7 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. Solve and check by substituting: 5x + 13 = 23 β†’ x = 2Prompt: To undo + 13, do the opposite.
  2. Solve: βˆ’x + 4 = βˆ’4 β†’ x = 8Prompt: First undo the addition: subtract 4 on both sides.

Watch out for

  • Doing an operation to one side of an equation but not the other.
  • Reading 3x as 3 + x, or thinking x always stands for one particular number.

Support and stretch

Support

  • Review first: Two-step equations.
  • Use concrete materials: balance scales or a balance drawing.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Move on to: Solve equations of the form p(x + q) = r; Solve two-step equations with a division; Write and solve two-step equations from real situations.
  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/math/grade-7.

Free lesson plan from eurekami.com/lesson-plan-builder

eurekami

Solve two-step equations with negative numbers

Name

Date

Score/ 8

  1. Question 1

    Solve: 5x + 16 = 26

    x =

  2. Question 2

    Solve: 1 βˆ’ 3x = βˆ’8

    x =

  3. Question 3

    Sam solved 3x βˆ’ 15 = βˆ’9 and got x = βˆ’8. Check by substituting, then give the correct solution.

    x =

  4. Question 4

    Solve: 8x βˆ’ 9 = βˆ’105

    x =

  5. Question 5

    Solve: 4 βˆ’ 2x = βˆ’14

    x =

  6. Question 6

    Sam solved 3x + 6 = 3 and got x = 3. Check by substituting, then give the correct solution.

    x =

  7. Question 7

    Solve: 4x βˆ’ 12 = βˆ’28

    x =

  8. Question 8

    Solve: 18 βˆ’ 8x = βˆ’38

    x =

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Answer key: Solve two-step equations with negative numbers

  1. 1. x = 2

  2. 2. x = 3

  3. 3. x = 2

  4. 4. x = -12

  5. 5. x = 9

  6. 6. x = -1

  7. 7. x = -4

  8. 8. x = 7