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Science lesson plan · 12th grade (Year 13 in England) · 45 minutes

Titration calculations

Chemical reactions, acids and bases

CCSS NGSS.HS-PS1-7CCSS NGSS.SEP 5England: GCSE Chemistry: Chemical changes (titrations, Higher)

Objective and success criteria

Students will: Titration calculations.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Concentration in mol/dm³; Neutralisation and naming salts

Leads to: the next skill in this area.

Materials: Teacher demo or video, Indicator color chart, Mini whiteboards, A diagram or short video clip of the idea, Printed student sheet (below).

Warm-up · 5 min

  • Quick retrieval from earlier learning (Concentration in mol/dm³; Neutralisation and naming salts). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. 1 mol of hydrochloric acid is in 500 cm³ of solution. What is the concentration, in mol/dm³? → 2 mol/dm³Prompt: concentration = moles ÷ volume in dm³
  2. Name the salt: calcium carbonate + hydrochloric acid → ___ + water + carbon dioxide (calcium oxide / calcium chloride / calcium nitrate / calcium sulfate) → calcium chloridePrompt: The first part of the salt's name comes from the metal.
  3. How many moles of sodium hydroxide are in 20 cm³ of a 1 mol/dm³ solution? → 0.02 molPrompt: moles = concentration × volume in dm³

Hook · 5 min

  • Drop an antacid tablet in water (or show a clip) and ask whether a new substance is being made.
  • Share the objective: Titration calculations. Read the success criteria together.

I do: model it · 10 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: 20 cm³ of 0.5 mol/dm³ sodium hydroxide is neutralised by 12.5 cm³ of hydrochloric acid. HCl + NaOH → NaCl + Hâ‚‚O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places.
  • Step 1: n(NaOH) = 0.5 × 0.02 = 0.01
  • Step 2: n(HCl) = 0.01
  • Step 3: 0.01 ÷ 0.0125 = 0.8
  • Step 4: So the answer is: 0.8 mol/dm³
  • Answer: 0.8 mol/dm³
  • Pause after each step and ask a student to say what comes next.

We do: guided practice · 10 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. 25 cm³ of 0.5 mol/dm³ sodium hydroxide is neutralised by 20 cm³ of hydrochloric acid. HCl + NaOH → NaCl + H₂O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places. → 0.625 mol/dm³Prompt: Find moles of sodium hydroxide: concentration × volume in dm³.
  2. Titres (cm³): rough 22.19, run 1 21.64, run 2 21.69. Ignoring the rough titre, calculate the mean titre from the concordant results (within 0.10 cm³), in cm³. Give 2 decimal places. → 21.67 cm³Prompt: The rough titre is only a guide.

You do: independent practice · 10 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 8 questions are on the student sheet below, with answers in the key.

Exit ticket · 5 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. What does "concordant results" mean in a titration? (results with different indicators / the first titre only / titres that agree closely, usually within 0.10 cm³ / titres that are exactly 25 cm³) → titres that agree closely, usually within 0.10 cm³Prompt: They show the method is repeatable.
  2. 20 cm³ of 0.1 mol/dm³ sodium hydroxide is neutralised by 22.5 cm³ of hydrochloric acid. HCl + NaOH → NaCl + H₂O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places. → 0.089 mol/dm³Prompt: Find moles of sodium hydroxide: concentration × volume in dm³.

Watch out for

  • Everyday meanings of words getting in the way of the science meaning: define key words explicitly.
  • Remembering facts without the reason: ask "why?" and "what is the evidence?"

Support and stretch

Support

  • Review first: Concentration in mol/dm³.
  • Use concrete materials: teacher demo or video.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/science/grade-12.

Free lesson plan from eurekami.com/lesson-plan-builder

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Titration calculations

Name

Date

Score/ 8

  1. Question 1

    What does "concordant results" mean in a titration?

    • A. the first titre only
    • B. titres that are exactly 25 cm³
    • C. titres that agree closely, usually within 0.10 cm³
    • D. results with different indicators
  2. Question 2

    Titres (cm³): rough 25.03, run 1 24.23, run 2 24.18. Ignoring the rough titre, calculate the mean titre from the concordant results (within 0.10 cm³), in cm³. Give 2 decimal places.

    Answercm³

  3. Question 3

    20 cm³ of 0.5 mol/dm³ sodium hydroxide is neutralised by 12.5 cm³ of hydrochloric acid. HCl + NaOH → NaCl + H₂O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places.

    Answermol/dm³

  4. Question 4

    Which piece of equipment measures exactly 25.0 cm³ of alkali into the flask?

    • A. a test tube
    • B. a volumetric pipette
    • C. a beaker
    • D. a measuring cylinder
  5. Question 5

    Titres (cm³): rough 25.79, run 1 24.69, run 2 24.64. Ignoring the rough titre, calculate the mean titre from the concordant results (within 0.10 cm³), in cm³. Give 2 decimal places.

    Answercm³

  6. Question 6

    20 cm³ of 0.5 mol/dm³ sodium hydroxide is neutralised by 25 cm³ of hydrochloric acid. HCl + NaOH → NaCl + H₂O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places.

    Answermol/dm³

  7. Question 7

    Titres (cm³): rough 24.7, run 1 23.95, run 2 23.85. Ignoring the rough titre, calculate the mean titre from the concordant results (within 0.10 cm³), in cm³. Give 2 decimal places.

    Answercm³

  8. Question 8

    20 cm³ of 0.2 mol/dm³ sodium hydroxide is neutralised by 16 cm³ of sulfuric acid. H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. What is the concentration of the acid, in mol/dm³? Give 3 decimal places.

    Answermol/dm³

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Answer key: Titration calculations

  1. 1. C. titres that agree closely, usually within 0.10 cm³

  2. 2. 24.21 cm³

  3. 3. 0.8 mol/dm³

  4. 4. B. a volumetric pipette

  5. 5. 24.67 cm³

  6. 6. 0.4 mol/dm³

  7. 7. 23.9 cm³

  8. 8. 0.125 mol/dm³