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Math lesson plan Β· 8th grade (Year 9 in England) Β· 30 minutes

Solve equations with brackets and x on both sides

Algebra

CCSS 8.EE.C.7.BEngland: KS3 AlgebraEngland: GCSE Foundation Algebra

Objective and success criteria

Students will: Solve equations with brackets and x on both sides.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Solve equations with x on both sides; Expand brackets with a negative multiplier

Leads to: Equations with one solution, no solution or infinitely many

Materials: Balance scales or a balance drawing, Algebra tiles, Function machine cards, Mini whiteboards and pens, Printed student sheet (below).

Warm-up Β· 4 min

  • Quick retrieval from earlier learning (Solve equations with x on both sides; Expand brackets with a negative multiplier). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. Expand βˆ’4(x βˆ’ 6). β†’ -4x+24Prompt: Multiply BOTH terms by βˆ’4.
  2. Solve: βˆ’3x + 4 = 3x + 22 β†’ x = -3Prompt: Add 3x to both sides so the x-term stays positive.
  3. Expand βˆ’4(x βˆ’ 7). β†’ -4x+28Prompt: Multiply BOTH terms by βˆ’4.

Hook Β· 3 min

  • Show a "think of a number" puzzle and ask the class to work out the starting number.
  • Share the objective: Solve equations with brackets and x on both sides. Read the success criteria together.

I do: model it Β· 7 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: Solve: 4(x + 4) = 2x + 8
  • Step 1: 4x + 16 = 2x + 8
  • Step 2: 2x = βˆ’8
  • Step 3: x = βˆ’4
  • Answer: x = -4
  • Pause after each step and ask a student to say what comes next.

We do: guided practice Β· 6 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. Solve: 3(x + 6) = 4x + 23 β†’ x = -5Prompt: Expand the brackets first.
  2. Solve: 5(x βˆ’ 4) = 4(x βˆ’ 2) βˆ’ 9 β†’ x = 3Prompt: Expand both brackets.

You do: independent practice Β· 7 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 6 questions are on the student sheet below, with answers in the key.

Exit ticket Β· 3 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. Solve: 5(x + 6) = 2x + 36 β†’ x = 2Prompt: Expand the brackets first.
  2. Solve: 5(x βˆ’ 5) = 6(x + 1) βˆ’ 37 β†’ x = 6Prompt: Expand both brackets.

Watch out for

  • Doing an operation to one side of an equation but not the other.
  • Reading 3x as 3 + x, or thinking x always stands for one particular number.

Support and stretch

Support

  • Review first: Solve equations with x on both sides.
  • Use concrete materials: balance scales or a balance drawing.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Move on to: Equations with one solution, no solution or infinitely many.
  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/math/grade-8.

Free lesson plan from eurekami.com/lesson-plan-builder

eurekami

Solve equations with brackets and x on both sides

Name

Date

Score/ 6

  1. Question 1

    Solve: 4(x βˆ’ 2) = 3(x + 2) βˆ’ 10

    x =

  2. Question 2

    Solve: 5(x + 2) = 6x + 13

    x =

  3. Question 3

    A rectangle is (x + 1) cm long and 3 cm wide. A square has sides of (x βˆ’ 3) cm. Their perimeters are equal, so 2(x + 1 + 3) = 4(x βˆ’ 3). Find x.

    x =

  4. Question 4

    Solve: 5(x βˆ’ 3) = 6(x βˆ’ 1) βˆ’ 7

    x =

  5. Question 5

    Solve: 5(x + 2) = 7x + 16

    x =

  6. Question 6

    A rectangle is (x + 3) cm long and 3 cm wide. A square has sides of (x βˆ’ 1) cm. Their perimeters are equal, so 2(x + 3 + 3) = 4(x βˆ’ 1). Find x.

    x =

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Answer key: Solve equations with brackets and x on both sides

  1. 1. x = 4

  2. 2. x = -3

  3. 3. x = 10

  4. 4. x = -2

  5. 5. x = -3

  6. 6. x = 8