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Math lesson plan · 8th grade (Year 9 in England) · 30 minutes

Equations with the unknown on both sides

Algebra

CCSS 8.EE.C.7England: KS3 AlgebraEngland: GCSE Foundation Algebra

Objective and success criteria

Students will: Equations with the unknown on both sides.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Two-step equations; Expand brackets (distributive property)

Leads to: Systems of linear equations (simultaneous equations); Rational equations; Solve equations with x on both sides

Materials: Balance scales or a balance drawing, Algebra tiles, Function machine cards, Mini whiteboards and pens, Printed student sheet (below).

Warm-up · 4 min

  • Quick retrieval from earlier learning (Two-step equations; Expand brackets (distributive property)). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. Expand: 3(x − 6) → 3x-18Prompt: Multiply every term inside the bracket by the number outside.
  2. Solve: −2x − 9 = 9 → x = -9Prompt: Add 9 to both sides.
  3. Expand: 4(x + 8) → 4x+32Prompt: Multiply every term inside the bracket by the number outside.

Hook · 3 min

  • Show a "think of a number" puzzle and ask the class to work out the starting number.
  • Share the objective: Equations with the unknown on both sides. Read the success criteria together.

I do: model it · 7 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: Solve: 5x + 10 = 6x + 17
  • Step 1: 5x + 10 = 6x + 17
  • Step 2: −x + 10 = 17
  • Step 3: −x = 7
  • Step 4: x = −7
  • Answer: x = -7
  • Pause after each step and ask a student to say what comes next.

We do: guided practice · 6 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. Solve: 3x − 3 = 2x + 1 → x = 4Prompt: Collect the x terms on one side.
  2. Solve: 2(x + 8) = 3(x + 5) + 5 → x = -4Prompt: Expand the brackets on both sides first.

You do: independent practice · 7 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 6 questions are on the student sheet below, with answers in the key.

Exit ticket · 3 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. Solve: 5x − 15 = 4x − 12 → x = 3Prompt: Collect the x terms on one side.
  2. How many solutions does 2x + 8 = 2x + 8 have? (No solution / Infinitely many solutions / Exactly one solution) → Infinitely many solutionsPrompt: Subtract the x terms from both sides. What is left?

Watch out for

  • Doing an operation to one side of an equation but not the other.
  • Reading 3x as 3 + x, or thinking x always stands for one particular number.

Support and stretch

Support

  • Review first: Two-step equations.
  • Use concrete materials: balance scales or a balance drawing.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Move on to: Systems of linear equations (simultaneous equations); Rational equations; Solve equations with x on both sides.
  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/math/grade-8.

Free lesson plan from eurekami.com/lesson-plan-builder

eurekami

Equations with the unknown on both sides

Name

Date

Score/ 6

  1. Question 1

    How many solutions does 5x + 5 = 5x + 7 have?

    • A. No solution
    • B. Infinitely many solutions
    • C. Exactly one solution
  2. Question 2

    Solve: 2(x + 3) = 1(x + 6) − 2

    x =

  3. Question 3

    Solve: 9x − 7 = 6x + 17

    x =

  4. Question 4

    How many solutions does 6x + 5 = 6x + 5 have?

    • A. No solution
    • B. Infinitely many solutions
    • C. Exactly one solution
  5. Question 5

    Solve: 6(x + 7) = 5(x + 8) + 11

    x =

  6. Question 6

    Solve: 8x − 2 = 3x + 23

    x =

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Answer key: Equations with the unknown on both sides

  1. 1. A. No solution

  2. 2. x = -2

  3. 3. x = 8

  4. 4. B. Infinitely many solutions

  5. 5. x = 9

  6. 6. x = 5