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Math lesson plan · 11th grade (Year 12 in England) · 30 minutes

Remainder and factor theorems

Algebra

CCSS HSA.APR.B.2CCSS HSA.APR.B.3

Objective and success criteria

Students will: Remainder and factor theorems.

  • I can answer questions on today's skill on my own, without help.
  • I can explain each step and say why it works.
  • I can check my answer and spot a mistake.

Before and after

Needs first: Add, subtract and multiply polynomials; Function notation

Leads to: Polynomial functions: zeros and end behaviour; Divide a polynomial by (x − a); Use the factor theorem to find an unknown coefficient

Materials: Balance scales or a balance drawing, Algebra tiles, Function machine cards, Mini whiteboards and pens, Printed student sheet (below).

Warm-up · 4 min

  • Quick retrieval from earlier learning (Add, subtract and multiply polynomials; Function notation). Students answer on mini whiteboards.
  • Show answers together and note who needs support in the main task.
  1. Simplify: (2x² + 6x − 9) + (x² − 6x + 3) → 3x^2-6Prompt: Remove the brackets.
  2. f(x) = x² − 6x − 7. Find f(−3). → 20Prompt: Replace every x with (−3).
  3. Expand and simplify: (−2x − 4)(x² − 3x − 4) → -2x^3+2x^2+20x+16Prompt: Multiply each term of the first bracket by every term of the second.

Hook · 3 min

  • Show a "think of a number" puzzle and ask the class to work out the starting number.
  • Share the objective: Remainder and factor theorems. Read the success criteria together.

I do: model it · 7 min

  • Work through the example out loud, saying why you do each step, not just what you do.
  • Example: Find the remainder when x³ − 3x² − 7x − 6 is divided by (x + 1).
  • Step 1: f(−1) = −1 − 3 + 7 − 6
  • Step 2: = −3
  • Answer: -3
  • Pause after each step and ask a student to say what comes next.

We do: guided practice · 6 min

  • Do these together. Students try each step on whiteboards before you reveal it.
  • Use the hints as prompts rather than giving the answer.
  1. Find the remainder when x³ + 2x² − 3x + 7 is divided by (x − 1). → 7Prompt: Remainder theorem: the remainder on dividing by (x − a) is f(a).
  2. (x − 5) is a factor of x³ − 3x² − 25x + 75. Solve x³ − 3x² − 25x + 75 = 0. Give all three solutions, separated by commas. → x = -5 or x = 3 or x = 5Prompt: Divide by the known factor to get a quadratic.

You do: independent practice · 7 min

  • Students work on the student sheet. Circulate and check the first two answers of every student early.
  • Students who finish: write a question of their own for a partner, with the answer.

The 6 questions are on the student sheet below, with answers in the key.

Exit ticket · 3 min

  • Two questions on their own. Sort answers into got it / nearly / not yet to plan the next lesson.
  1. Find the remainder when x³ − 3x² + 3x − 11 is divided by (x + 3). → -74Prompt: Remainder theorem: the remainder on dividing by (x − a) is f(a).
  2. (x + 5) is a factor of x³ − 21x + 20. Solve x³ − 21x + 20 = 0. Give all three solutions, separated by commas. → x = -5 or x = 1 or x = 4Prompt: Divide by the known factor to get a quadratic.

Watch out for

  • Doing an operation to one side of an equation but not the other.
  • Reading 3x as 3 + x, or thinking x always stands for one particular number.

Support and stretch

Support

  • Review first: Add, subtract and multiply polynomials.
  • Use concrete materials: balance scales or a balance drawing.
  • Give the first step of each question, or a partly worked example to finish.
  • Pair with a confident partner for the guided practice.

Stretch

  • Move on to: Polynomial functions: zeros and end behaviour; Divide a polynomial by (x − a); Use the factor theorem to find an unknown coefficient.
  • Explain a common mistake in writing and how to fix it.
  • Write a word problem that uses today's skill, then solve a partner's.

Homework and more practice

Free online practice with hints and printable worksheets for this skill: eurekami.com/math/grade-11.

Free lesson plan from eurekami.com/lesson-plan-builder

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Remainder and factor theorems

Name

Date

Score/ 6

  1. Question 1

    Find the remainder when x³ − 2x² + 2x + 8 is divided by (x − 3).

    Answer

  2. Question 2

    (x + 2) is a factor of x³ + 2x² − 16x − 32. Solve x³ + 2x² − 16x − 32 = 0. Give all three solutions, separated by commas.

    x =

  3. Question 3

    Find the remainder when x³ + x² + x − 8 is divided by (x + 3).

    Answer

  4. Question 4

    (x − 4) is a factor of x³ + 4x² − 17x − 60. Solve x³ + 4x² − 17x − 60 = 0. Give all three solutions, separated by commas.

    x =

  5. Question 5

    Find the remainder when x³ + 6x² + 6x + 6 is divided by (x + 1).

    Answer

  6. Question 6

    (x + 4) is a factor of x³ + 4x² − 25x − 100. Solve x³ + 4x² − 25x − 100 = 0. Give all three solutions, separated by commas.

    x =

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Answer key: Remainder and factor theorems

  1. 1. 23

  2. 2. x = -4 or x = -2 or x = 4

  3. 3. -29

  4. 4. x = -5 or x = -3 or x = 4

  5. 5. 5

  6. 6. x = -5 or x = -4 or x = 5